Calculator Riddle

SOLUTION:

Finding the Value of One Clock
Using the first equation: 9’oclock+9’oclock+3’oclock=219’o clock + 9’o clock + 3’o clock = 219’oclock+9’oclock+3’oclock=21 9+9+3=219 + 9 + 3 = 219+9+3=21 Therefore, 1 Clock = 3.

Determining the Value of a Calculator
According to the second equation: 3calculators=303 calculators = 303calculators=30 Thus, one calculator = 10.

The sum of numbers inside the calculator is: 1+2+3+4=101 + 2 + 3 + 4 = 101+2+3+4=10 Therefore, the calculator’s value depends on the sum of the numbers inside it.

Solving for the Bulb
According to the third equation: 1Bulb+1Bulb–1Bulb=151 Bulb + 1 Bulb – 1 Bulb = 151Bulb+1Bulb–1Bulb=15 Canceling out the bulbs, we get: 1Bulbwithfivelights=151 Bulb with five lights = 151Bulbwithfivelights=15 Therefore, one bulb with one light = 3.

For a bulb with four lights: 4×3=124 × 3 = 124×3=12

Final Equation
The final equation is: 9’oclock+Calculator(1+2+2+4)x3bulbs(withfourlightseach)9’o clock + Calculator (1+2+2+4) x 3 bulbs (with four lights each)9’oclock+Calculator(1+2+2+4)x3bulbs(withfourlightseach)

Translating the final equation into numbers: 9+(1+2+2+4)x3(12)9 + (1+2+2+4) x 3(12)9+(1+2+2+4)x3(12) 9+9×36=9+324=3339 + 9 x 36 = 9 + 324 = 3339+9×36=9+324=333

So, the answer is 333.

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